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How to display Dependent drop-down value using ajax call with dynamically

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Title unchanged

How to display Dependent drop-down value using ajax call with dynamically

Category unchanged

Tutorials

Yii version changed

1.1

Tags changed

drop down list, ajax link, search, #dropdown

Content changed

[...]
**1)** First we have to create the two table and insert the some sample data




 ```php

CREATE TABLE `country_master` (
`id` INT(11) UNSIGNED NOT NULL AUTO_INCREMENT,
[...]

 ```php

CREATE TABLE `state_master` (
`id` INT(11) UNSIGNED NOT NULL AUTO_INCREMENT,
[...]

 ```php

<?php echo CHtml::hiddenField('hidden_state',$model->state);?>
```
[...]

 ```php

<div class="control-group">
<?php echo $form->label($model,'country',array('class'=>'control-label')); ?>
[...]

 ```php

<div class="control-group">
<?php echo $form->label($model,'state',array('class'=>'control-label')); ?>
[...]

 ```php

public function actionDynamicStates()
{
[...]

 ```php

class UtilityHtml extends CHtml{
[...]

 ```php

<?php
Yii::app()->clientScript->registerScript('countryload','jQuery(function($) {
$("#VkUsers_country").trigger("change");
$("#VkUsers_state").val(\''.$model->state.'\');
});
[...]
1 1
6 followers
Viewed: 49 752 times
Version: 1.1
Category: Tutorials
Tags: #dropdown, ajax link, drop down list, search
Written by: Ankit Modi
Last updated by: samdark
Created on: Jul 23, 2014
Last updated: 5 years ago
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