[Helecta]

How return current URL with anchors?
Example: I'm in page www.sitename#anchor
I want get full URL www.sitename#anchor, not www.sitename.
Yii::app()->request->getUrl() isn't suitable for this purpose

[Keith]

The anchor part isn't sent to the server by the browser, so PHP can never see it.

More info here:
http://stackoverflow...tion-of-the-url

If you need it, you could use javascript to send it in a separate request.

[zaccaria]

You can't get the anchor as it is not submitted to the server. If you need it you have to do an ajax request.

[Luiz Celso]

PHP can't get ancors.

Happy coding.

[Helecta]

Maybe i don't see simple solution.
I used extension rrgridview.
I use filters and choose one of record and go to it update.
I need to return back after i save all changes.
How can i do it, if i can't get (easily) anchors of url?

[Jaggi]

to pass something in via the url you will need to use a GET or POST method. GET would be simplier if it isn't sensitive information, e.g. ?id=12&sitename=something

[krowe]

The first step is to get the grid view to generate the correct links. You'll want to add a new variable to each link (I use a variable named redir). So add the appropriate line of this to your grid view definition:

    ...
    'buttons'=>array(
        'update' => array(
            'url'=>'Yii::app()->createUrl(Yii::app()->controller->id."/update", array("id"=>$data->id, "redir"=>Yii::app()->controller->id."/admin"))',
        ),
        ...

Next, you'll want to modify your controller action:

...
if($model->save()) {
  if(isset($_GET['redir']) $this->redirect($_GET['redir']);
  else $this->redirect('whatever_you_want_to_make_the_default_action');
}

This is completely untested code, YMMV.