Ajax Delete Get parameter from URL

Yii 1.1 General Discussion
1

I have an ajax checkbox that displays data or removes products depending on which boxes are checked. I’m facing two issues

  1. If I manually deselect all checkboxes the last set of products always show

  2. I have a deselect all function that deselects all checkboxes but the products still remain in the view

Looking at firebug I can see the "GET URL" still has all the selected checboxes inside the URL even tho none of my chekboxed have the tick sign (none are checked).

I want to know if there’s a way I can delete/remove the GET URL, so when I deselect all the URL is just the page address.

e.g.

That’s when some items are selected, if I use deselect all that URL doesn’t change so my products still show, basically I need a

function that will result in

Below is my JS code


Yii::app()->clientScript->registerScript('search',

    "var ajaxUpdateTimeout;

    var ajaxRequest;

	

	$('.pro').change(function(){

    products = $('.pro').serialize();   

    $.fn.yiiListView.update(

        'ajaxListView',

        {data: products}

    );

});


   $('#selectAll').click(function(){

        $('.pro').attr('checked','checked')    

        products = $('.pro').serialize();

        $.fn.yiiListView.update(

            'ajaxListView',

            {data: products}

        );

    });

    $('#selectNone').click(function(){

        $('.pro').removeAttr('checked')

        products = $('.pro').serialize();

        $.fn.yiiListView.update(

            'ajaxListView',

            {data: products}

        );

    });




"


	

);

Thanks in advanced